6x^2+4x=13

Solution for 6x^2+4x=13 equation:

6x^2+4x=13

We move all terms to the left:

6x^2+4x-(13)=0

a = 6; b = 4; c = -13;
Δ = b2-4ac
Δ = 42-4·6·(-13)
Δ = 328
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{328}=\sqrt{4*82}=\sqrt{4}*\sqrt{82}=2\sqrt{82}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-2\sqrt{82}}{2*6}=\frac{-4-2\sqrt{82}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+2\sqrt{82}}{2*6}=\frac{-4+2\sqrt{82}}{12}
$